Tension conceptual problem..?
When a mass goes in a horizontal circle with speed V at the end of a string of length L on a frictionless table, the tension in the string is T. If the speed of this mass were doubled, but all else remained the same, the tension would be either 2T, 4T, sqrt2*T, or T/(sqrt2)
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Tension in this problem is equal to mv^2/r.
Doubling the mass and tangential velocity of the object would result in this:
(m * (2v)^2) / r = (m * 4 * v^2) / r = 4T
Newton's 2nd Law applied to circular motion is T=mv^2/r. Since v is squared, doubling it adds a factor of 4, so the answer is 4T.