a straight trail with uniform inclination of 15 degrees leads from a lodge at an elevation of 900 ft to a mountain lake at an elevation of 7800 ft. what is the lenght of the trail?
You don't need the law of cosines, just the law of sines.
The trail is the hypotenuse of a right-angled triangle. The angle of the hypotenuse is 15°. The opposite side is 7800 - 900 = 6,900 feet (height difference between lodge and lake). Let the trail length be a, the opposite side be b, and the trail incline be B. A is thus 90°, because it lies opposite the hypotenuse.
Ummmmmmmmmm do u need the work proven??? Regulation of sines is a/SinA=b/SinB=c/SinC... (the capital letters are angles and the lowercase ones are aspects go to mode to your calculator and prefer levels... (: i had the same obstacle
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Verified answer
sin 15⁰ = 6900 / h
h = 6900 / sin 15⁰
h = 26660 ft is length of trail to nearest foot.
You don't need the law of cosines, just the law of sines.
The trail is the hypotenuse of a right-angled triangle. The angle of the hypotenuse is 15°. The opposite side is 7800 - 900 = 6,900 feet (height difference between lodge and lake). Let the trail length be a, the opposite side be b, and the trail incline be B. A is thus 90°, because it lies opposite the hypotenuse.
a/sin A = b/sin B
a = b sin A/sin B
a = 6,900 × sin 90/sin 15
a = 6,900 × 1/sin 15
a = 26,660 feet.
Ummmmmmmmmm do u need the work proven??? Regulation of sines is a/SinA=b/SinB=c/SinC... (the capital letters are angles and the lowercase ones are aspects go to mode to your calculator and prefer levels... (: i had the same obstacle