Two 13-cm-diameter electrodes 0.48 cm apart form a parallel-plate capacitor?
Two 13-cm-diameter electrodes 0.48 cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 15 V battery.
What is the charge on each electrode?
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Assuming an air gap between the plates, the capacitance is
C = ε0*A/s,
where A is the plate area and s the separation
A = π*d²/4 use d = 0.13 m and s = 0.0048m for s and ε0 = 8.89*10^-12 F/m to get C
Then Q = V*C