Two identical positive charges... Physics help!?
Two identical positive charges exert a repulsive force of 6.9 × 10^−9
N when separated by
a distance 4.4 × 10^−10 m.
Calculate the charge of each. The Coulomb
constant is 8.98755 × 10^9 N · (m^2/C^2)
Answer in units of C
Thanks!
Answers & Comments
Verified answer
From F = K*q*q/D² we get
q = D√[F/K] = 4.4E-10√[6.9E-9/8.98755E9] = 3.855E-19 C
use tension formulation for electric tension F = 6.5*10^-9 N = ok *Q*Q/r^2 ok = 9.0 * 10^9 r = 3.6*10^-10 rearange the equation for Q on my own Q^2 = F*r^2/ok Q = sqrt ( F*r^2/ok) Q = 3.06*10^-19 coul I purely put in the values in case you dont like applying ok use Q = sqrt(F*r^2*4*pi*e) the place e is permitivity of loose area.