Word Problem on Algebra 1?
The moment of ineartia of a ring spinning on an axis throughit's center & along the axis of symmetry is given by the formula l=MR^2, where M is the mass of the ring & R is the radius of the ring. Use this information to find the radius of a ring of mass 0.42 & moment of inertia 0.04 kg/m^2.
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I'm assuming, since you didn't use units, that the mass is 0.42 kg. If the mass given is not in kg, you would need to convert it before plugging it into the equation.
So you have:
I=0.04kg/m^2
M=0.42 kg
and R is unknown. The equation is I=MR^2, so plug what you know into the equation.
0.04=0.42R^2 Divide both sides by 0.42
0.095=R^2 Take the square root of the equation
R=0.31 m