1-2log(7x)=log(10) on base 10 - log(7x)^2 in base 10 so it becomes log(10/7x^2) in base 10
well you cold write it as log(7x)^-2
log [10 / (49)*(x^2) ]
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1-2log(7x)=log(10) on base 10 - log(7x)^2 in base 10 so it becomes log(10/7x^2) in base 10
well you cold write it as log(7x)^-2
log [10 / (49)*(x^2) ]