A coefficient in front of a logarithm comes from an exponent inside of the logarithm. So a*log(x) = log(x^a). Two logarithms added together are the same as one logarithm multiplied together. So log(x) + log(y) = log(x*y). Use these properties to solve your problem.
2log(x) + 4log(x+9)
log(x^2) + log((x+9)^4)
log((x^2) * ((x+9)^4)); This is your final answer.
Have a better day than whatever day Donny wished you to have! Just kidding, you're a pleasant man, Donny.
Answers & Comments
Verified answer
A coefficient in front of a logarithm comes from an exponent inside of the logarithm. So a*log(x) = log(x^a). Two logarithms added together are the same as one logarithm multiplied together. So log(x) + log(y) = log(x*y). Use these properties to solve your problem.
2log(x) + 4log(x+9)
log(x^2) + log((x+9)^4)
log((x^2) * ((x+9)^4)); This is your final answer.
Have a better day than whatever day Donny wished you to have! Just kidding, you're a pleasant man, Donny.
Take this piece by piece using log properties:
2logx + 4log(x+9)
logx^2 + log(x+9)^4
log(x^2)(x+9)^4
Have a good day!
2log(x) + 4log(x + 9)
= log(x^2) + log[(x + 9)^4]
= log[x^2(x + 9)^4]
= log{[x(x + 9)^2]^2}
= 2log[x(x + 9)^2]
log (x^2)(x+9)^4