Ln y^3 + 1/3(x^3y^6) - 5 ln y
The answer in the back is Ln X
Not sure to get to there.. Help?
If it were
ln y^3 + 1/3ln(x^3y^6) - 5 ln y =
ln y^3 + ln(x^3y^6)^1/3 - ln y^5 =
ln[y^3*xy^2/y^5] =
ln (x)
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If it were
ln y^3 + 1/3ln(x^3y^6) - 5 ln y =
ln y^3 + ln(x^3y^6)^1/3 - ln y^5 =
ln[y^3*xy^2/y^5] =
ln (x)