Verified answer

y = 2 is horizontal line (parallel to the x axis) passing through y = 2

No matter what x you use, the answer for y is always 2

Your first one is y = 5 - x^2

so the points where they intersect are when 5 - x^2 = 2

x^2 = 3

x = +-sqrt(3)

(-sqrt3, 2) and (sqrt3, 2)

Easy, all you have to do is rule a straight line through y = 2, so that y will always be equal to 2 along the line. It's that simple. Then, check where the two graphs intersect and note the x and y coordinates.

Hope that helps, if you have any further questions feel free to ask. :)

The first function is a parabola y = - (x^2-5) or y = - x^2 + 5

The second function is a linear function y = 2

Then, when we want to know the points where the two graphs intersect, we do: first function = second function

- x^2 + 5 = 2

x1 = + (3)^(1/2)

x2 = - (3)^(1/2)

You know where it says "2" on the y axis?

Draw a horizontal line straight through it.

Where it crosses the graph's line - bam - those are your results.

go to the number 2 on the y-axis. Now draw a horizontal line, straight across, left& right.

Your points will be at (0,2), (1,2), (2,2)........(-1,2), (-2,2)...etc

Notice for all of them, no matter what the x-value is.....y=2 (hence the equation)

Your x is any real number, it's not really limited.