Verified answer

y^2(y+3)-4(y+3)

(y^2-4)(y+3)

(y+2)(y-2)(y+3)

Hey there!

Use grouping to factor the problem.

y^3+3y^2-4y-12 -->

y^2(y+3)-4(y+3) -->

(y^2-4)(y+3) -->

(y-2)(y+2)(y+3)

So the answer is (y-2)(y+2)(y+3).

Hope it helps!

y^3+3y^2-4y-12

-> (y^2-4) * (y+3)

(y^2-4) = (y+2) * (y-2)

Answer: (y+2) * (y-2) * (y+3)

Factor out a y from the variant terms:

(y)(y^2 +3y - 4) -12

=y(y+4)(y-1)-12

y(y^2+3y-4y)-12

y(y-3)(y-1)-12

(y-12)(y-3)(y-1)

(y+3)(y-4)(y-3)(y-1)

(y-4)(y-1)