angular physics problem?
.25kg ball bounces the ground with incoming velocity of 32m/s @ an angle of 45 degree and bounces out at 28m/s @ 45 degree whats the change in momentum?
.25kg ball bounces the ground with incoming velocity of 32m/s @ an angle of 45 degree and bounces out at 28m/s @ 45 degree whats the change in momentum?
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Verified answer
Initial momentum = .25 * 32 = 8 kg.m/s
Final Momentum = .25 * 28 = 7 kg.m/s
Change in momentum = 8 - 7 = 1kg.m/s