Okay so I have a big quiz tomorrow and I'm having trouble with changes atm into Kpa! I'm working on these practice problems and i have been given the anwser sheet and i am so confused! Some of the anwsers are correct when i multiple atm by 101.325 and some are only correct if i multiply it by 101.8! Does it really matter if the digit is about 2 off? Ill give you a problem so I can explain it better...
If I have an unknown quantity of gas at a pressure of 1.20 atm, a volume of 31.0 liters, and a temperature of 87.0 0C, how many moles of gas do I have?
So the correct anwser according to the anwser sheet is 1.26mol and i used that one by multiplying it by 101.325
If I have 7.70 moles of gas at a pressure of 0.09 atm and at a temperature of 56.0 0C, what is the volume of the container that the gas is in?
this one is supposed to be 2310L but when i multiplies the atm by 101.325 i got 2308L and it is only correct when i times it by 101.8!??!?!?!
Does it matter what equation you use to solve the equation! Please help!!! And do you think my teacher will mark it down if i miss the anwser by about 2 numbers!!!???
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1 atm = 101.325 kPa, perhaps the number was slightly off due to a rounding error or significant figures? If you use the conversion 1 atm = 101.325 kPa your teacher should not mark you down for anything.
T temperature to be measured on kelvin scale.. i.e. 19+273 ok and no of moles.. weight divided by using molecular weight fee of R 2 b chosen accordin to the instruments used for pressur en quantity.. if u use atm-l then the fee of R is 0.0821 if u use pascal-m^3 fee is 8.314 and for calculation of warmth or skill in energy, fee of R shud be approximated to 2