how much thermal energy does it take to melt a 50g piece of ice originally at 0 degress C and bring it to a temperature of 37 degrees C?
50g ice @ 0deg C ---> 50g water @ 0deg C [= latent heat of fusion of ice * 50 = 80Cal/g/deg C X 50g = 4000Cal]
---> 50g water @ 37deg C = 37 X 50 = 1850 Cal
Total heat = 5850 Cal
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50g ice @ 0deg C ---> 50g water @ 0deg C [= latent heat of fusion of ice * 50 = 80Cal/g/deg C X 50g = 4000Cal]
---> 50g water @ 37deg C = 37 X 50 = 1850 Cal
Total heat = 5850 Cal