The electric potential at a position located a distance of 21.0 mm from a positive point charge of 7.10×10^-9C and 14.5 mm from a second point charge is 1.18 kV. Calculate the value of the second charge.
**I know the answer is -2.999×10^-9 C, but i just need to know how to do the work to get that answer. Any help with this would be great. Thanks.
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There is insufficient information to obtain an answer.
Forces are vectors and direction makes a difference.
If I push something right with my left hand and to the left with my right hand there will be very little movement of the object being pushed compared to the energy my muscles are using. In such a situation the net force is effectively the difference between the scalar value that describes the strength of force being applied by each arm.