( ^ = to the power of )
6c^3-12cd^3-15cd / 3cd
whats that equal ??!!
thank you
you dont have to define the symbol ^. That IS what it means.
3 + 4 = 7
Where "+" is the addition sign... okay?
(6c^3-12cd^3-15cd) / 3cd
(2c^2 / d) - (4d^2) - 5
-12cd^3+6c^3-5
Divide each and every term by 3cd, or better, factorize the first polynomial first and then simplify:
3c(c^2 - 4d^3 - 5d) / 3cd = (c^2 - 4d^3 - 5d) / d
Cheers,
Kempos
(6c^3-12cd^3-15cd)/3cd
=216c^3/3cd-1728c^3d^3/3cd-15cd/3cd
=72c^2/d-576c^2d^2-5
ans
2cd^2/d - 4cd^2 - 5
(1/d)(2c^2-4d^3-5d)
or
(2c^2/d) - 4d^2 - 5
I don't know
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Verified answer
you dont have to define the symbol ^. That IS what it means.
3 + 4 = 7
Where "+" is the addition sign... okay?
(6c^3-12cd^3-15cd) / 3cd
(2c^2 / d) - (4d^2) - 5
-12cd^3+6c^3-5
Divide each and every term by 3cd, or better, factorize the first polynomial first and then simplify:
3c(c^2 - 4d^3 - 5d) / 3cd = (c^2 - 4d^3 - 5d) / d
Cheers,
Kempos
(6c^3-12cd^3-15cd)/3cd
=216c^3/3cd-1728c^3d^3/3cd-15cd/3cd
=72c^2/d-576c^2d^2-5
ans
2cd^2/d - 4cd^2 - 5
(1/d)(2c^2-4d^3-5d)
or
(2c^2/d) - 4d^2 - 5
I don't know