69.8% iron; 30.2% oxygen
83.7% carbon; 16.3% hydrogen
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We consider 100 g
we have 69.8 g of Fe => 69.8 g / 55.847 = 1.25 moles
we have 30.2 g of O => 30.2g/ 16 = 1.89
We divide by the smallest number
1.25 / 1.25 = 1
1.89 / 1.25 = 1.5
We get FeO1.5
To get whole numbers we multiply by 2 and we have
Fe2O3
In the same way
Moles C = 83.7 / 12.011 = 6.97
Moles H = 16.3 / 1.00794 = 16.17
CH2.3
2.32 x3 = 6.96
We get C3H7
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Verified answer
We consider 100 g
we have 69.8 g of Fe => 69.8 g / 55.847 = 1.25 moles
we have 30.2 g of O => 30.2g/ 16 = 1.89
We divide by the smallest number
1.25 / 1.25 = 1
1.89 / 1.25 = 1.5
We get FeO1.5
To get whole numbers we multiply by 2 and we have
Fe2O3
In the same way
Moles C = 83.7 / 12.011 = 6.97
Moles H = 16.3 / 1.00794 = 16.17
CH2.3
2.32 x3 = 6.96
We get C3H7