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a million. lnx+ln(2x+a million)=0 because of the fact the log of a product is the sum of the logs, you are able to write this equation as ln x(2x+a million) = 0 it particularly is such as x(2x+a million) = e^0 = a million 2x^2 + x - a million = 0 (2x - a million)(x + a million) = 0 x = a million/2 or x = -a million for sure you are able to desire to reject the x=-a million on account that ln (-a million) does not exist. For selection 2, take ln of the two facets and remedy for x. (straightforward)