Bond energies question!?
NBr3 + 3H2O --> 3HOBr + NH3
The energy exchange associated with this reaction in -81 kJ.
Use this information to calculate the energy of the N-to-Br bond. Assume all atoms other than hydrogen obey the octet rule.
Thanks!!! Any help is welcome!!
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Bonds broken = 3 x N-Br and 6 x O-H
Bonds formed = 3 x O-H, 3 x O-Br and 3 x N-H
You are told that bonds broken - bonds formed = -81kJ/mol.
Three of the O-H bonds cancel out, but now all you have to do is look up the relevant bond energies, and work out N-Br.