I don't have a clue how to do this question...
1+lnx
all help is appreciated, thanks
1 can be expressed as ln(e). and ln(a)+ln(b) = ln(ab).
so 1+lnx can be written as ln(e)+lnx = ln(ex)
1 + lnx = ln(e) + lnx
=> ln(ex)
:)>
Copyright © 2024 Q2A.ES - All rights reserved.
Answers & Comments
Verified answer
1 can be expressed as ln(e). and ln(a)+ln(b) = ln(ab).
so 1+lnx can be written as ln(e)+lnx = ln(ex)
1 + lnx = ln(e) + lnx
=> ln(ex)
:)>