Verified answer

2x^2 yz - 32x^2 y^3 z

= -2x^2yz (16y^2 - 1)

= -2x^2yz(4y - 1)(4y + 1)

Edit: Re: Negative? If it has a negative in front and not a dash, then:

- 2x^2 yz - 32x^2 y^3 z

= -2x^2yz(16y^2 + 1)

-2x^2yz ( 1+16y^2)

Notice that you can factor out the same value from both terms: (-2x^2yz)

This would leave you with:

(-2x^2yz) * (1 + 16y^2)

The other answers did not get the negative correct! When you factor out the negative from both terms, they will both become positive terms.

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Additional Details:

both Iceman and Girl got it wrong.

-2x^2yz(1+16y^2) [I used GCF of terms]

Factorize*

1.) 2x^2yz(1 - 16y^2)

2x^2yz(4y - 1) (4y + 1)

IF problem is "2x^2 yz - 32x^2 y^3 z"

OR

2.) -2x^2yz(1 + 16y^2)

IF problem is "- 2x^2 yz - 32x^2 y^3 z"

basically taking the traditional component from the given difficulty. We get, (a million+x) + y (a million+x) + z (a million+y) + xz (a million+y) Taking user-friendly component of a million+x, a million+y (a million+x)(a million+y) + (a million+y)(z)(a million+x) Now Taking user-friendly component (a million+x), (a million+y) (a million+x)(a million+y)(a million+z)