when 125 mL of H2O at 20 degree celcius are mixed with 85 mL of water at 81.8degree celcius, what is the final temperature?
assume that no heat is lost to the surroundings; d(h2O) = 1 g/mL
heat * volume = heat * volume
{(125mL * 293K) + (85mL * 354.8K)}/210mL = 318K
= 45 degrees.
choose as best answer please
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Verified answer
heat * volume = heat * volume
{(125mL * 293K) + (85mL * 354.8K)}/210mL = 318K
= 45 degrees.
choose as best answer please