how to calculate potential energy?
A charge of -0.20 C is moved from a position where the electric potential is 18 V to a position where the electric potential is 60 V. What is the change in potential energy of the charge associated with this change in position?
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Energy = ½ • Q • V
∆Energy = ½ • Q • ∆V = ½ • (-0.2) • (60 − 18) = - 4.2 J