math question logarithms?
10^6 times 2^(t/20) = 2^(t/15)
how would you solve for t
explain and show steps
More Questions From This User See All
10^6 times 2^(t/20) = 2^(t/15)
how would you solve for t
explain and show steps
Copyright © 2024 Q2A.ES - All rights reserved.
![BHH [Bustin' Ho's Heads]](https://q2a.es/img/profile/B/BHHvvBustinvvx27vvHovvx27vsvHeadsv.jpg)
Answers & Comments
Verified answer
(10^6) * 2^(t/20) = 2^(t/15)
10^6 = 2^(t/15) ÷ 2^(t/20)
10^6 = 2^(t/15-t/20)
10^6 = 2^((20t-15t)/300)
10^6 = 2^(5t/300)
10^6 = 2^(t/60)
log(10^6) = log(2^(t/60))
6 = (t/60)log2
t = 360/log2
t = 1196 to 4 s.f.
I hope this helps. Note that I've used logs to the base 10.