Resistor and inductor in parallel?
An 50.0 ohm resistor and a 200-mH inductor are connected in parallel across a 100-V (rms), 60.0 Hz
source.
(a) What is the rms current in the resistor?
(b) By what angle does the total current lead or lag
behind the voltage?
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Answers & Comments
Verified answer
A) Current in resistor = (100 V) / (50 Ohms) = 2 Amps (RMS)
B) Inductive reactance: 2 Pi f L = 2 Pi (60 Hz)(0.2 H) = 75.4 Ohms
Impedance of parallel combination
Z = (75.4 i)(50) / ( 75.4i + 50 ) = 34.7 + 23.0i = 41.7 Ohms at 33.5 degrees
The total current is therefore (100V) / Z = 2.4 Amps at -33.5 degrees
Inductor Parallel
Ir=100/50=2
XL=377*.2=75.4
Il=100/(j 75.4)
It=Ir+il You do the math.
A) Vrms=Irms*R therefore Irms= Vrms/ R Vrms= Vmax (sqrt2) Irms = (100)/(50) = 2 A
B) Since we are talking about a inductor, it will lead by 90 degrees