ugh general physics help please?
A particle's position is given by x = 3.00 - 15.00t + 3t2, in which x is in meters and t is in seconds. Where is the particle when it momentarily stops?
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A particle's position is given by x = 3.00 - 15.00t + 3t2, in which x is in meters and t is in seconds. Where is the particle when it momentarily stops?
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A hint: When the particle stops the speed is zero. Using calculus you can find the "t" when dx/dt=0