y^(-1) is the same as writing 1/y.
So 1/1/y, using the division converting to multiplication rule this is the same as writing 1*y/1 which is equal to y.
Hint 1: y^0 = 1
Hint 2: y^(+1)=y
Hint 3: y^(a) * y^(b) = y^(a+b)
1 / (y^(-1)) = 1 / (y^(-1)) * (1)
1 / (y^(-1)) = 1 / (y^(-1)) *(y/y)
1 / (y^(-1)) = (1*y) / [y^(-1) *y]
1 / (y^(-1)) = (1*y) / [y^(-1) *y^(+1)] (Hint 2)
1 / (y^(-1)) = (y) / y^[(-1) + (+1)] (Hint 3)
1 / (y^(-1)) = y / y^(0)
1 / (y^(-1)) = y / 1 (Hint 1)
1 / (y^(-1)) = y
Simple. y^(-1) = 1/y . 1/(1/y) = y.
u can write y^-1 as 1/y...
so y^-1=1/y
1 divided by 1/y=1/1*y/1
1/1*y/1=y...
just try using paper n pen...:)
if u didn't get stil, i'll explain further...
(something)^-1 or 1/(something) means a reciprocal of (something).. so if you are doing 1/(y^(-1)), it means you are taking a reciprocal of a reciprocal.. so y goes up!
hope it helps.
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y^(-1) is the same as writing 1/y.
So 1/1/y, using the division converting to multiplication rule this is the same as writing 1*y/1 which is equal to y.
Hint 1: y^0 = 1
Hint 2: y^(+1)=y
Hint 3: y^(a) * y^(b) = y^(a+b)
1 / (y^(-1)) = 1 / (y^(-1)) * (1)
1 / (y^(-1)) = 1 / (y^(-1)) *(y/y)
1 / (y^(-1)) = (1*y) / [y^(-1) *y]
1 / (y^(-1)) = (1*y) / [y^(-1) *y^(+1)] (Hint 2)
1 / (y^(-1)) = (y) / y^[(-1) + (+1)] (Hint 3)
1 / (y^(-1)) = y / y^(0)
1 / (y^(-1)) = y / 1 (Hint 1)
1 / (y^(-1)) = y
Simple. y^(-1) = 1/y . 1/(1/y) = y.
u can write y^-1 as 1/y...
so y^-1=1/y
1 divided by 1/y=1/1*y/1
1/1*y/1=y...
just try using paper n pen...:)
if u didn't get stil, i'll explain further...
(something)^-1 or 1/(something) means a reciprocal of (something).. so if you are doing 1/(y^(-1)), it means you are taking a reciprocal of a reciprocal.. so y goes up!
hope it helps.