You are asked to design a parallel-plate capacitor having a capacitance of 0.937 F and a plate separation of 2.44 mm. Calculate the required surface area of each plate. Answer in units of m^2 .I am unsure about were to start here! Please help! Explain yourself too! will choose best answer!. Created by Dee. science-mathematics-en - physics-en

C = εo * A/d--> A = C * d/εo = 0.937 * 2.44 x 10^-3/8.85 x 10^-12 = 2.58 x 10^8 m^2