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The area of triangle with sides a and b and included angle C is
A = ½ab sin(C).
The angle between the two 16 unit side lengths is C = 180° - 54° - 54° = 72°.
A = ½(16)(16)sin(72°) ≈ 121.7
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The area of triangle with sides a and b and included angle C is
A = ½ab sin(C).
The angle between the two 16 unit side lengths is C = 180° - 54° - 54° = 72°.
A = ½(16)(16)sin(72°) ≈ 121.7