Physics Problem! (energy!)?
A 755 N diver drops from a board 10.0 m above the water's surface. Find the diver's speed 5.00 m above the water's surface. Then find the diver's speed just before striking the water.
P.S. Please show work too!!!
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Verified answer
PEi + KEi = PEf + KEf
mghi + 0 = 0 + 1/2mvf^2
755(5) = 1/2(77.04)vf^2
3775 = 1/2(77.04)vf^2
7550 = 77.04 vf^2
98.001 = vf^2
vf = 9.899 m/s
For the other part,
PEi + KEi = PEf + KEf
mghi + 0 = 0 + 1/2mvf^2
755(10) = 1/2(77.04)vf^2
7550 = 1/2(77.04)vf^2
15100 = 77.04 vf^2
196.002 = vf^2
vf = 14 m/s
I hope i did this right good luck.