Question on displacement current of parallel plate capacitor?
A sinusoidally-varying voltage V(t) = Vosinωt with amplitude Vo = 10 V and frequency of f = ω/(2π) = 100 Hz is impressed across the plates of a circular-shaped parallel plate air-gap capacitor of radius a = 1.0 cm and plate separation d= 0.01 mm. The amplitude of Maxwell's displacement current ID flowing across the gap between the plates of this capacitor is:
(a) 0.28 × 10-6 A
(b) 1.75 × 10-6 A
(c) 3.50 × 10-6 A
(d) 6.30 × 10-6 A
(e) 9.45 × 10-6 A
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Verified answer
Choice B
Solution:
1. C = (epsylon_o)(A) / d = 2.78x10^-10 F
2. X(c) = 1 / (2*pi*f*C) = 5.72x10^6 ohms
3. i = V / R = 10 / 5.72x10^6 = 1.75x10^-6 A
Displacement Current Parallel Plate Capacitor
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